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Author Topic: physics high school magnification question?  (Read 233 times)
Kunegunda_Dymek
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« on: June 20, 2011, 01:07:19 AM »

Use the thin lense equation to calculate the image distance of the formed by a 2 cm high object that is located 6 cm from a concave (diverging) lens having a focal length of -3 cm.


What will be the magnification of this image?
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JullyWum
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« Reply #1 on: June 20, 2011, 05:35:41 AM »

Using 1/v = 1/f - 1/u

adding data and signs ..
1/v = 1/(-3) - 1/6 = - 0.5
 ►v = - 2.0 cm (on same side of lens as object and virtual)


Magnification = v/u = 2/6 = 1/3
Height of image = 1/3*2.0cm .. .. ►0.67
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